Answer to Find dy/dx y*sin(2x) = x*cos(2y) By signing up, you'll get thousands of stepbystep solutions to your homework questions You can `dy/dx=1/(xy log10)cdot(yx cdot dy/dx)` In the line above we have applied the chain rule because `log(xy)` is a composite function On top of that we have applied product rule for `xy` to get 4 Given ∮C((y − sin(x))dx cos(x)dy) Using Green's theorem, you should use C, so you get ∮C((y − sin(x))dx cos(x)dy) = ∮C(Pdx Qdy) = ∫2π 0 dx∫2x / π 0 dy(∂Q ∂x − ∂P ∂y) = − ∫2π 0 dx∫2x / π 0 dy(sin(x) 1)
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14.find (dy)/(dx) if y=cos(log x+e^(x))
14.find (dy)/(dx) if y=cos(log x+e^(x))-Solution for dy Using the parametric differentiation find dx if x = 12 cos t , y = 3 sin t 025 tan t 400 sin t 1500 025 cot t 025 Stack Exchange network consists of 177 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack Exchange




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Find dy/dx y=(\sin x\cos x)^{2} 🚨 Hurry, space in our FREE summer bootcamps is running out 🚨 Ex 55, 3 Differentiate the functions in, (log𝑥 )^cos𝑥 Let 𝑦=(log𝑥 )^cos𝑥 Taking log both sides log𝑦 = log〖〖 (log𝑥 )〗^cos𝑥 〗 log𝑦 = cos〖𝑥 〖log 〗(log𝑥 ) 〗 Differentiating both sides 𝑤𝑟𝑡𝑥 𝑑(log𝑦)/𝑑𝑥 = 𝑑(cos〖𝑥 〖 log 〗(log𝑥 ) 〗 )/𝑑𝑥 𝑑(log𝑦ডিই এর সমাধান x cos y dy = (x e ^(x) log x e ^(x)) dx হয় Updated On To keep watching this video solution for FREE, Download our App Join the 2 Crores Student community now!
Find dy/dx, when If x = e^(cos 2 t) and y = e^(sin 2t), prove that dy/dx = (y log x)/x log y asked Apr 17 in Differentiation by Kaina ( 304k points) differentiationSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreShow \iint \cos\frac {xy} {xy}\, dx\,dy=\frac {\sin1} {2} over the region R Let R be the region bounded by x y = 1,x = 0,y = 0 Show ∬ cos xyx−y Your way for solving the problem is right but you may lose the proper range of u and v Try to draw the triangle region and then find the corresponding vertices according to the
solve the following differential equation x cos y dy xex log x ex dx Mathematics TopperLearningcom rn73oni66 Starting early can help you score better!Find d2y/dx2 where y=log(x^2/e^2) y=log(x 2 /e 2 ) diff wr to x , we get dy/dx=1/(x 2 /e 2 ) (2x/e 2 ) =2/x diff wr to x again d 2 y/dx 2 =2/x 2 ThankAnswer a/x for x > 0 Method 1 y = a log x dy/dx = d/dx(a log x) = a d/dx (log x) = a 1/x = a/x for x > 0 (Proved) Method 2 We will arrive at the same result from first principle, using the basic definition of dy/dx as a limit Let y = ϕ (x) =



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Calculus 1 Answer Epsilon Explanation please see the image file to explanation Answer link Related questions How do I determine the molecular shape of a molecule?Calculus Find dy/dx y = natural log of cos (x) y = ln (cos(x)) y = ln ( cos ( x)) Differentiate both sides of the equation d dx (y) = d dx (ln(cos(x))) d d x ( y) = d d x ( ln ( cos ( x))) The derivative of y y with respect to x x is y' y ′ y' y ′ Differentiate the if y=(log) cosx x 2 1/x 21 find dy/dx Share with your friends Share 1 We have, y = log x cos x x 2 1 x 2




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Let y =(log x) x x log x Also, let u =(log x) x and v = x log x ∴ y = u v `⇒"dy"/"dx" = "du"/"dx""dv"/"dx"` (1) u = (logx) x ⇒ log u = log(log x) x यदि y= log cos x^(2)," तो "(dy)/(dx)" पर "x=0 का मान है Updated On 2 To keep watching this video solution for FREE, Download our App Join the 2 Crores Student community now!The derivative of the function `y = log(x 1/x)` with respect to x, `dy/dx` has to be determined It is assumed that log in the problem refers to natural logarithm




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if x cosy y cosx 1then find the value of dy dx Mathematics TopperLearningcom 9qo6ekrr Starting early can help you score better! Dy by dx of y=log √1cosx by 1cosx 291 रवीन्द्र रोज सुबह 800 बजे घर से निकलता है और 9 30 बजे कार्यालय पहुँचता है। एक दिन उसने अपना घर 800 बजे छोड़ा, लेकिन सामान्य गति से 3/4 की गति पर If y=log( base cos x) sinx{log (base sin x) cos x}^1 sin ^1 {2x/(1x^2)} find dy/dx at x = pi/4 Maths




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Let y = log(cos e x) By using the chain rule, we obtain `"dy"/"dx" = "d"/"dx""log"(cos"e"^"x")` `= 1/cos"e"^"x" "d"/"dx"(cos"e"^"x")` ` = 1/(cos"e"^"x") Find dy/dx, if y=log sin x^2 neha287 neha287 Math Secondary School answered Find dy/dx, if y=log sin x^2 2 See answers chiyal chiyal Dy/dx =( 1/sinx^2 ) cosx^2 2x plz fir se SYED777 SYED777 Y=log sin x^2= dy/dx=1/sin x^2(cos x^2)(2x)=2x cot x^2 plz fir se btao pura solutionDifferential coef fi cient of sin –1 x Let y = sin –1 x ⇒ sin y = x Differentiating wrt x 2 –1 2 dy cos y 1 dx dy 1 dx cos y 1 1– sin y d 1 ie, (sin x) dx 1– x = = = = 512 DIFFERENTIATION OF INVERSE TRIGONOMETRIC FUNCTIONS




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Ex 5 4 10 Differentiate W R T X In Cos Log X E X Teachoo
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